"Love Thy Enemy" Cup

[SeraphimLeftNut]

Annoucing "Love Thy Enemy" Cup

The tournament will consist of two phases. The firs phase will last one week, with players playing for the highest score in the two pools. The second phase will be the BO5 final between the two players that get the highest score in the two respective pools.

The score is calculated by the attached formula at the end of phase one.

The score is calculated from games exclusively in each pool.

For a game to be counted in pool A, it must be played on Regor VI, it must be played during the phase one time period and it must be reported on this forum.

For a game to be counted in pool B, it must be played on Sathira Beach v2, it must be played during the phase one time period and it must be reported on this forum.

A report consist of: attached replay, winning player name, losing player name.

Rules:

1. Can play in both pools

2. Can play each enemy at most one time in each pool

3. Games can be reported by third parties as long as one of the players involved has already been reported as a participant.

4. If the same player has the highest score in both pools then the second highest score from either pool will be the other player in the final

5. Draws do not count for anything and the two players can replay the game.

First Cup

Phase one: Sunday 30th MArch, Sunday 6th April (game time)

Phase two: Sunday 6th April, Sunday 13th April
BO5 on Craftius Maximus, Theta 2, Crag Dunes, Regor VI, Sathira Beach v2. Tie breaker: Blasted Rock repeatedly.

Monetary prize: Will scale with the number of participants, with 100 USD maxiumum.

[Mr-Smith]

how you count draws

[Blackheart]

Can anybody explain how this works using an example?

[SeraphimLeftNut]

People play games and report them here.
All players will have x wins and y losses.
To calculate the score for each player the given formula will be used.

If you get a win against someone who gets a win you benefit the most.
If you get a loss against someone who wins a lot you benefit as much as getting a loss against someone who wins a lot.
The score is normalized to the number of games, however playing more games will put you at an advantage against others.
Playing against those who play many games is the best strategy to get the highest score.

Example:
Zock beats ZLO
ZLO beats BH
BH beats Zock
Nombringer beats Zock
BH beats Nombringer

Zock score: (0.5+1+0.5+0.5+0.5)/(sqrt(3))
(ZLO_loss+ZLO_win+BH_win+BH_win+Nombringer_win)/sqrt(number of games by Zock)

[Lu_Xun_17]

Can you play two times the same opponent?

[SeraphimLeftNut]

Can you play two times the same opponent?

Rule 2

[manread]

is there a lower limit for rank on this? sounds fun, if confusing (rank ~800 btw)

[SeraphimLeftNut]

There are no limits on who can play

[Vee]

Interesting tourney! If I'm not mistaken, your formula can be simplified:

Code: Select all

score = (total wins of enemies + total games of enemies that you beat) / (4+2*sqrt(your total games))

[SeraphimLeftNut]

Interesting tourney! If I'm not mistaken, your formula can be simplified:

Code: Select all

score = (total wins of enemies + total games of enemies that you beat) / (4+2*sqrt(your total games))

yes total games on enemies = total losses+total wins of enemies

I hope that people actually play it