to calculate distance, where enemy will be when bullet fall i add, to corrent enemy position, enemy direction * distance from unit * bullet speed scale * enemy velocity. This will tell us where enemy will be when bullet fall.
- Code:
enemyPosition = enemy1_.transform.position-barel_.transform.position;
enemyDistance = Vector3.Distance(enemy1_.transform.position, transform.position);
enemyVelocity = enemy1_.rigidbody.velocity.magnitude;
distance_ = enemyPosition + enemy1_.transform.forward * enemyDistance * 0.13f * enemyVelocity ;
But now i must calculate how rotate barrel to angle, when bullet will fell into good place, where enemy will be. First I had to check what is minimum and maximum angle that give us minimum and maximum range. In arty t1 70-90 degrees is ok, just tested it. This is based on strength of the shot and how quickly bullet falls by gravity.
minimum angle + maximum*inverted distance from target from 0 to 1.
- Code:
invertedDistance = (30-distance_.magnitude)/30);
barel_.localRotation = Quaternion.Euler(new Vector3(70.0f+(20.0f*invertedDistance , 0, 0));
next interesting thing is how to quickly turn unit, tower etc. where is the smallest path - when we rotate left or right. We can simply check angle between unit direction and target, but this dont tell us how rotate. I found answer for that in engine documentation. Ido not fully understand these calculations but it may be useful to someone
- Code:
dirA = transform.forward - Vector3.Project (transform.forward, Vector3.up);
dirB = (target.position - transform.position)*Time.deltaTime - Vector3.Project ((target.position - transform.position), Vector3.up);
angle = Vector3.Angle (dirA, dirB);
rotationAngle = angle * (Vector3.Dot (Vector3.up, Vector3.Cross (dirA, dirB)) < 0 ? -1 : 1);
rigidbody.angularVelocity = (Vector3.up * rotationAngle * 0.1f);
Time.deltaTime - frame time
transform.position - unit position
transform.forward - unit direction
Vector3.up - axis on which we want to rotate
Statistics: Posted by ozonex — 29 Jul 2012, 16:00
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